On Wednesday 15 October 2003 22:05, bob pilly wrote: > Yes it is what i expect to be stored in the array.
[snip] > That is one array stored in $rslt[0] and another in $rslt[1] (perhaps i > am not understanding arrays correctly?) > > The thing that confuses me is if i assign the contents of an array member > to a variable, and then print it, i get the result i am after,for example > > $avar = $rslt[0][1];print $avar; > will return '4' as i would expect from the output of print_r. Well it *should* work. If you go back to the code that you posted at the beginning of this thread, correct the errors and run it, you'll see that it works fine. -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * ------------------------------------------ Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general ------------------------------------------ /* We will have solar energy as soon as the utility companies solve one technical problem -- how to run a sunbeam through a meter. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
