Sure --
<?
$this_date = "1/1/2003";
for($i=1; $i<=365; $i++) {
if (date("l", strtotime($this_date) == "Friday")) {
echo $this_date . "<br>";
}
$this_date = date("n/j/Y",mktime(0,0,0,date("m",
strtotime($this_date)),date("d", strtotime($this_date))+1,date("Y",
strtotime($this_date))));
}
?>
Shew wrote:
> Hi,
>
> I'm trying to find a formula for displaying the date for every Friday of a
> given year, i.e. 2003
>
> Jan 3, 2003
> Jan 10, 2003
> Jan 17, 2003
> etc.
>
> Any ideas?
>
> Thanks
>
> --
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