John A. Thomason wrote:
Thanks, that did it. And yes, I am trying to run this as a shell script.
Thank you very much.

John.

----- Original Message ----- From: "John Nichel" <[EMAIL PROTECTED]>
To: "John A. Thomason" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Saturday, July 12, 2003 10:01 PM
Subject: Re: [PHP] OK, So I am new to these List. Win2000 help!




John A. Thomason wrote:

The following is my output in the command prompt window(DOS Prompt?)

C:\PHP>hello.php
Content-type: text/html
X-Powered-By: PHP/4.3.2

!#C:\php\;
echo"Hello World!";
if ($foo):
echo "yep\n";
elseif ($bar):
echo "almost\n";
else:
echo "nope\n";
endif;
phpinfo();
C:\PHP>

And the following is the PHP code to generate it.

!#C:\php\;

echo"Hello World!";

if ($foo):

echo "yep\n";

elseif ($bar):

echo "almost\n";

else:

echo "nope\n";

endif;

phpinfo();

Now, I know that the variables are not set, so they should be false, but

the

output just displays a "listing" of the code and doesn't process it. In

the

documentation, it states that PHP can be run from the command prompt,

like a

batch file. Now what am I doing wrong.

I do have it working correctly with an Apache server, that I am using
backend.

and my install dir is "C:\php", and it is listed first in the path.

John A. Thomason

[EMAIL PROTECTED]


Looks like you're trying to run it as a shell script, or a cgi program. Replace the sh-bang on the first line with <?php and make sure the last line of the script is ?>

eg:

<?php
echo"Hello World!";
if ($foo):
echo "yep\n";
elseif ($bar):
echo "almost\n";
else:
echo "nope\n";
endif;
phpinfo();
?>

Yeah, you just need to enclose the actual script in the opening/closing php tags (<?php and ?>). And to run it as a shell script, you can either call the script as...


c:\path\to\php\php.exe filename.php (or just 'php filename.php' if the php interperter is in your path), or put the sh-bang as the first line (before the opening php tag).


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