"Jacky@lilst" wrote:
>
> People
> If I run a sniplet like this:
>
> **********************
> $query="select name from foo";
> $result= mysql_query($query);
> while($row = mysql_fetch_row($result))
> stuffssss.......to display record found....
> ...
> ***********************
> what am I suppose to do if I also want the code to be able to deal with the case
>that no record found and redirect user to other page?
Hello,
In the PHP Manual, section MySQL, there is a description of a function
called mysql_num_rows()...
Robert
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