a) $menu[] = array("name" => $db->f("name"), "url" => $db->f("topic_id"));
b) echo $menu[0]["name"]; //for example - depends on what you want to do
BTW have a look into the manual, the array stuff is described pretty well
Pavel
----- Original Message -----
From: "Matt Williams" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; "PHP_UK@egroups. com" <[EMAIL PROTECTED]>
Sent: Wednesday, February 21, 2001 3:56 PM
Subject: [PHP] array headaches
> Hi
>
> could anybody please help me get my head around the following.
>
> I get some url information from the database (title, url)
> I am trying to then put this into an array so I can pass it to the page to
> display a menu.
> so
> a) how do I get the data into the array. would this be the way to do it??
>
> $menu = array();
> while($db->next_record())
> {
> $menu[]["name"] = $db->f("name");
> $menu[]["url"] = $db->f("topic_id");
> }
> which leads me onto
> b) how do I get the data back out. I can't test to see if the above works
as
> I can't get at the data
>
> TIA
>
> M@
>
>
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