> $nameArray = array("Last", "Suffix", "Prefix", "First", "Middle");
> while (list($key, $value) = each ($nameArray)){
> if ($infoObject->$value != ""){
> echo "$infoObject->$value"; #this is the problem line...
> }
> }
> ************
>
> If I take out the "$infoObject->" on the problem line, the correct value
is
> displayed. But while "$infoObject->" is present, the error is given. I
> assumed that $value would be a string since the array is of strings. If I
> used mysql_fetch_array and used $value for the index of the array, would
the
> same thing happen? Thanks for the help.
Try getting rid of the quotes in your problem line, and then switch to
mysql_fetch_array if that doesn't help.
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