Yes, I can see that I didn't put the ";" after "$test1=array()".
Fortunately, I just type up the code example to this newsgroup. So, excuse
my typo error.
Thanks for the clarification and offering of the use of PHP code such as
print_r() or var_dump(). They are new to me. So, it was a great help when
I was debugging the missing data in the huge array (containing several more
arrays).
Thanks,
Scott
""Scott Fletcher"" <[EMAIL PROTECTED]> wrote in message
94pkll$516$[EMAIL PROTECTED]">news:94pkll$516$[EMAIL PROTECTED]...
> Hi!
>
> When I use the echo to see what is inside the list(). Instead I got
the
> message on screen saying "ArrayArray".
>
> The array are being assigned first then then list come second. ie.
>
> $test = array();
> $test1 = array()
>
> list($test,$test1);
>
> ---------------
> When I do "echo list($test,$test1);", it doesn't work.
>
> What are the better way to see the data in the array?
>
> Thanks,
> Scott
>
>
>
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