Re: [PHP] Outputting specific HTML for <table> tag.

> 5 photos that need returning to one of the photo pages, and I have the
> photos in rows of three;  Obviously, there'd be an empty table cell.  And

> <?
>
> //  Connection code
>
> $table = "<table border=\"0\" /* Yadda Yadda */ >";
>

$table .= "<tr>";
$photocount = 0;

> while($row = mysql_fetch_array($result)) {
>
>     $row = $photo['photo'];
>
#> $table .= "<tr><td>$photo</td>"
#> $table .= "<td>$photo</td></tr>";

$table .= "<td>$photo</td>";
$photocount++;

if (($photocount % 3) == 2){
    #time to start a new row:
    $table .= "</tr><tr>";
}

>
>     }

$table .= "</tr>";

> $table .= "</table>";
>
> //  End Crap programming.
>
> ?>

The % operator is the "modulo" operator, aka "clock arithmetic".

Using $x % 3 makes it "count by threesies" and "wrap-around" to 0 when you
pass 2...

Anyway, when you hit '2', it will dump out the end row and new row tags.

BTW:  Any particular reason for building up the $table variable instead of
just spewing it out to the browser with echo (or print)?...  Unless you are
building some kind of template system, you are just making life hard on
yourself with it...

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