ID: 37149 Updated by: [EMAIL PROTECTED] Reported By: troelskn at gmail dot com -Status: Open +Status: Bogus Bug Type: Feature/Change Request Operating System: * PHP Version: * Assigned To: helly New Comment:
Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php doesn't matter, you still cannot use it in array functions Previous Comments: ------------------------------------------------------------------------ [2006-04-20 18:43:08] troelskn at gmail dot com I has the interface of an array. Thus, in a logical sense it _is_ an array. Changed the category to "Feature/Change Request". ------------------------------------------------------------------------ [2006-04-20 18:18:30] [EMAIL PROTECTED] Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php it is an object not an array, use "instanceof ArrayAccess" ------------------------------------------------------------------------ [2006-04-20 16:14:44] troelskn at gmail dot com Description: ------------ Using is_array() on an instance of ArrayObject returns FALSE. While strictly speaking this is true, it would make sense to return TRUE in most application-level code. Expected result: ---------------- A solution could be to add an argument to is_array, which relaxes the check to include ArrayObject. Eg. : bool is_array ( mixed var, [bool strict] ) $obj = new ArrayObject(); is_array($obj, FALSE); // returns TRUE is_array($obj); // returns FALSE ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=37149&edit=1
