ID: 33229 Updated by: [EMAIL PROTECTED] Reported By: fab097 at gmail dot com -Status: Open +Status: Closed Bug Type: Feature/Change Request Operating System: linux PHP Version: 4.3.10 New Comment:
Added to PHP 5.1 as date('o'); Previous Comments: ------------------------------------------------------------------------ [2005-06-03 11:46:04] fab097 at gmail dot com Description: ------------ using date("Y",$date) and date("w",$date) is not clean to get the YEARWEEK of a date. in most of case it looks to work, for example : with date of first or march 2005, it gives "2005" and "9" but on certain cases, it's not possible to get REAL YearWeek of a date. for example : date of 30th of december 2003 is the FIRST week of year 2004 ! then date("w",$date) gives correct week number : 1 but date("Y",$date) gives year 2003 (which is normal) a function YEARWEEK is missing. in mySQL I have such a function : select YEARWEEK('20031231',1); returns "200401" there are no way in php to get such result with date. PS : please as mysql add an optional parameters to this function to support first day of the week. (0=sunday, 1=monday) thank you. Reproduce code: --------------- $d=mktime(0,0,0,12,30,2003); echo date("d/m/y",$d)."\n"; echo "Year :".date("Y",$d)." Week :".date("W",$d); echo "\n expected YEARWEEK() : '200401'"; Expected result: ---------------- the required result of YEARWEEK future function is 200401 Actual result: -------------- this function does not exist yet, so.. no result. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=33229&edit=1