ID: 31956 Updated by: [EMAIL PROTECTED] Reported By: pillepop2003 at yahoo dot de -Status: Open +Status: Bogus Bug Type: Scripting Engine problem Operating System: * PHP Version: 4CVS, 5CVS (2005-02-13) New Comment:
Don't mix my example with yours, mine is passing something else than an array index to the function. And this is actually (kind of) documented as undefined: http://www.php.net/manual/en/language.references.pass.php See the last paragraph, about what can be passed by reference: "Any other expression should not be passed by reference, as the result is undefined." Previous Comments: ------------------------------------------------------------------------ [2005-02-13 20:29:19] pillepop2003 at yahoo dot de <?php function func1(&$a) { // void(); } var_dump($c); func1($c); var_dump($c); ?> should IMO output array(2) { ["one"]=> int(1) } array(2) { ["one"]=> int(1) } Why should the non-existing variable get a value (of NULL) - this is a paradoxon, isn't it? Can't it just be "not mentioned"? ------------------------------------------------------------------------ [2005-02-13 18:14:24] [EMAIL PROTECTED] What would you expect this to output: <?php function func1(&$a) { // void(); } var_dump($c); func1($c); var_dump($c); ?> IMO, this is exactly what you'd expect. The non-existing variable (or in your example, non-existing array index) gets value of NULL. I don't see what else should happen.. ------------------------------------------------------------------------ [2005-02-13 17:57:31] [EMAIL PROTECTED] This happens with both PHP_4_3 and HEAD from today. (only verified that it happens. I don't know if it's intentional or not :) ------------------------------------------------------------------------ [2005-02-13 17:27:23] pillepop2003 at yahoo dot de Description: ------------ Bug #26030 realtes to the same problem and should be reopened: Why? It seems to be *NOT* related to #25996, as formerly reported by [EMAIL PROTECTED], which was the reason to close it. Problem: If a part of an array, that does not yet exist, is passed to a function by reference, this part will be created automatically and filled with NULL. As long as no there is no function implemented to delete the NULL entry (unset does not work), this behavior cannot be correct. Please see my example - it clearly states that the behavior is incorrect. Reproduce code: --------------- See why: The following behavior *cannot* be intentional: <?php function func(&$a) { // void(); } $a['one'] =1; func($a['two']); ?> var_dump($a) returns array(2) { ["one"]=> int(1) ["two"]=> NULL } Expected result: ---------------- array(2) { ["one"]=> int(1) } Actual result: -------------- array(2) { ["one"]=> int(1) ["two"]=> NULL } ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=31956&edit=1
