ID:               30292
 User updated by:  devish at zonnet dot nl
 Reported By:      devish at zonnet dot nl
 Status:           Bogus
 Bug Type:         Output Control
 Operating System: Windows XP
 PHP Version:      5.0.1
 New Comment:

I was first thinking of that to, but that wasn't it.

A qoute out of my php.ini

error_reporting  =  E_ALL

; Print out errors (as a part of the output).  For production web
sites,
; you're strongly encouraged to turn this feature off, and use error
logging
; instead (see below).  Keeping display_errors enabled on a production
web site
; may reveal security information to end users, such as file paths on
your Web
; server, your database schema or other information.
display_errors = On


Previous Comments:
------------------------------------------------------------------------

[2004-09-30 15:16:13] [EMAIL PROTECTED]

You will not get a notice here, but a parse error, because this syntax
is not valid. 
Set display_errors to "on" and you should see it.

------------------------------------------------------------------------

[2004-09-30 15:03:59] devish at zonnet dot nl

Description:
------------
When declaring an array but don't initialize it, it stops running the
script. When declaring a normal variable it will just produce a
Undefined variable notice.

In the reproduce code it will not print "hello"

Offcourse this sort of code is rearly used, but the reason for
reporting this is that it doesn't report a notice or any warning.

Im running Win XP, with Apache 2.0 and only have one extension in my
php.ini (the mysql extension)



Reproduce code:
---------------
<?php
error_reporting(E_ALL);

$int[];

print "hello";
?>

Expected result:
----------------
I expect:
Notice: Undefined variable: int in E:\www-root\sqlite\test.php on line
4
hello

I See:
white screen



------------------------------------------------------------------------


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