#21912 [Com]: getimagesize() on remote images fails sometimes..

[michael dot mauch at gmx dot de]

 ID:               21912
 Comment by:       michael dot mauch at gmx dot de
 Reported By:      tozz at kijkt dot tv
 Status:           Verified
 Bug Type:         GetImageSize related
 Operating System: Linux
 PHP Version:      4.3.1-dev
 New Comment:

Yes, it's the same here - on the local servers it works with both
images, but it doesn't work with the 00645.jpg when I put it on another
remote server.

When I change line 387 of ext/standard/image.c:

                if ((marker = php_stream_getc(stream)) == EOF)
into
                marker = php_stream_getc(stream);
                fprintf(stderr,"%0x ",marker);
                if (marker == EOF)

I see
  e0 ff ed ff ee ff db ff c0
when the image is served from localhost and only
  e0 ff ed 68
or
  e0 ff ed 64 
when fetching from the remote servers. That looks strange, but I'm
afraid I don't understand what's going on here.


Previous Comments:
------------------------------------------------------------------------

[2003-02-08 05:41:17] [EMAIL PROTECTED]

I suppose ther is another problem :-)

When i download the image and put it on one of my local servers it
works:

[marcus@zaphod php4-HEAD]$ php -r 'print_r(getimagesize($argv[1]));' --
http://zaphod.boerger.de/php/ext/exif/test/bug21912.jpg
Array
(
    [0] => 389
    [1] => 500
    [2] => 2
    [3] => width="389" height="500"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)
[marcus@zaphod php4-HEAD]$ php -r 'var_dump(getimagesize($argv[1]));'
-- http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg
bool(false)

------------------------------------------------------------------------

[2003-01-28 13:52:36] tozz at kijkt dot tv

Yes, it has indeed something to do with the image. If I take another
image it works fine! But there must be some difference in the PHP
versions since the 2nd pictures only works with PHP 4.1.2, and not with
the latest PHP version.

------------------------------------------------------------------------

[2003-01-28 13:26:00] michael dot mauch at gmx dot de

php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";);
print_r($size); echo "\n";'

works without problems here (PHP 4.3.0), while

php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";);
print_r($size); echo "\n";'

prints nothing. ImageMagick's "identify" sees some strange ipct data in
the second image; probably these make getimagesize() misbehave.

------------------------------------------------------------------------

[2003-01-27 17:25:35] [EMAIL PROTECTED]

I can reproduce this with latest stable CVS (4.3.1-dev)
It does work if the image is local..but not if it's remote.


------------------------------------------------------------------------

[2003-01-27 16:12:37] tozz at kijkt dot tv

Hallo,

I have a weird problem, which I think is a bug. The following script
works with PHP 4.1.2 (I know, very outdated), but DOES NOT work with
PHP 4.3.0:

<?
error_reporting (E_ALL);

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");

print ("<p>\n");

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");
?>

The problem is :

The first image works fine, it shows the height, width and type.
However, the information about the second image is only beeing
displayed if using PHP 4.1.2. With PHP 4.3.0 no information is beeing
displayed.


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Edit this bug report at http://bugs.php.net/?id=21912&edit=1