Edit report at https://bugs.php.net/bug.php?id=29992&edit=1
ID: 29992 Comment by: paul dot dillinger at gmail dot com Reported by: fletch at pobox dot com Summary: foreach by reference corrupts the array Status: Not a bug Type: Bug Package: Scripting Engine problem Operating System: linux PHP Version: 5.0.1 Block user comment: N Private report: N New Comment: I still say this is a bug, so here's all the code you need to re-produce it: <pre> <?php $packages = array(); $library_names = array(); $ext_js = array( array( 'name' => 'myname1', 'attrib' => 'something1', 'package' => true, 'library_name' => 'package1' ), array( 'name' => 'myname2', 'attrib' => 'something2', 'package' => true, 'library_name' => 'package1' ), array( 'name' => 'myname3', 'attrib' => 'something3', 'package' => false ), array( 'name' => 'myname4', 'attrib' => 'something4', 'package' => false ) ); foreach($ext_js as &$item){ if(!empty($item['package'])){ $packages[] = $item; // Not using &, so should be a copy, not a reference corrent? $library_names[] = $item['library_name']; unset($item); } } if(!empty($packages)){ /*A*/ print_r($ext_js); foreach($packages as $item){ /*B*/ print_r($ext_js); } } ?> </pre> Look at the output on the last item. Instead of unset removing the item from the array $ext_js (which is what I thought it would do), it corrupts the array. The array is fine though unless you go in to another foreach using another $item. Changing the variable name on the second foreach to something OTHER than $item (I used $itemm) fixes it. Bug. Previous Comments: ------------------------------------------------------------------------ [2012-10-25 07:37:08] email at stevemann dot net I don't think this is going to go anywhere - seems to have reached a stalemate. So I have just retrained my head to automatically create foreach loops thus: foreach($array as $item){ }unset($item); If you need access to the last $item outside the loop, then just do it somewhere before the unset($item). Seems to me this thread is being accessed periodically by developers scratching their heads after discovering similar oddities happening with their foreach loops. My advice would be to do something similar to the above and just live with it. ------------------------------------------------------------------------ [2012-10-24 22:11:44] newms87 at gmail dot com I understand this functionality, and I do agree that it is not a bug. It seems at the core of PHP that this is what would happen, but it does seem very unintuitive to me having used a variety of other languages. The result is not expected and has caused several very hard to find bugs for me. Would it be possible to have PHP generate a E_NOTICE when using the same $var in both a foreach and afterwards when in a higher scope? EG: foreach($args as &$a){} $a = 'hello'; // this would generate an E_NOTICE Then maybe have the option to turn off (or on by default) the E_NOTICE warnings in the ini settings? ------------------------------------------------------------------------ [2012-06-29 18:52:20] iam4webwork at hotmail dot com I appreciate the explanation that Rasmus provides -- thank you! One small but troublesome detail: The first foreach changes the array by making $a[1] a reference variable while $a[0] remains a normal variable. $a = array(1,2); foreach($a as &$e){} var_dump($a,$e); // $a[1] == &int 2 $e == 2 foreach($a as $e){} $a[1] == &int 1 $e == 1 var_dump($a,$e); // $a[1] now points to last value of $a which is $a[0] How about adding a switch so that users who don't want or understand this behavior can turn it off? Then it would be up in front of the documentation and would be less liable to be overlooked by users who fail to scroll down to the colored box. Even if PHP were to have lexical scope (how hard would that be to implement and why can't PHP evolve that way?), that doesn't change the fact that the first loop doing seemingly nothing, does change the array. ------------------------------------------------------------------------ [2012-05-04 08:04:56] email at stevemann dot net ras...@php.net asked "Ok, simple question then. Do you expect this to output 3?" foreach(array(1,2,3) as $b) { } echo $b; I would much prefer it not to output 3. Personally I think it would make a lot more sense and be a lot safer to have the array element references scoped to the foreach block - so effectively being unset after the block has run. Having the last element of the array floating around outside of the block is very dangerous in my view and can lead to silent errors. As someone else mentioned, I hate to think how much incorrect data there is out there because of the last array element being accidentally changed outside of the block. der...@php.net rather flippantly said: "no, we can't unset it by default, as people might use this for some weird reason." I can think of plenty of non-weird reasons why people might want this behaviour. But if it was unset by default, it's a simple matter to assign the reference to a variable defined outside of the block thereby making it available outside the foreach. In other words, like this: $c = NULL; foreach(array(1,2,3) as $b) { $c = $b; } unset($b);// simulates block-scoping of $b echo $c; This is not a bug, but I believe it's dangerous behaviour of PHP as it would seem quite logical to assume that the element references are scoped to the foreach block only - witness the many comments in this thread to that effect. So my vote would be to change this behaviour to block-scoping in a future version. ------------------------------------------------------------------------ [2012-03-19 18:51:24] paul dot dillinger at gmail dot com Rasmus, Thanks for looking at this. I found the problem. I would still call it a bug, but I will describe it and you can decide. You are the man after all. You were right, I was passing a variable by reference in the few lines of code in front of my example above: foreach($this->data['external_'.$type] as &$item){ if(!empty($item['package'])){ $packages[] = $item; $library_names[] = $item['library_name']; unset($item); } } /* Code in example above goes here */ BUT, where I see this as a bug was: $packages (the array that was getting changed) was a new array created from the data of each $item. $packages was never being referenced, though the variable $item it was created from was. So, it should be a copy of the data and not THE data right? I fixed it by simply not trying to pass by reference and changing unset($item) to unset($this->data['external_'.$type]). Looking at it, that was the way to do it from the beginning. I see that, but I'm not sure why $packages gets changed down the road (it was correct immediately after this, but it and all copies of it change inside the next foreach). Any thoughts? ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at https://bugs.php.net/bug.php?id=29992 -- Edit this bug report at https://bugs.php.net/bug.php?id=29992&edit=1