Edit report at https://bugs.php.net/bug.php?id=43236&edit=1

 ID:                 43236
 Comment by:         jay-php at vengefulstapler dot com
 Reported by:        zyss at mail dot zp dot ua
 Summary:            "if set" and "if not set" functions (ifset, ifnset)
 Status:             Not a bug
 Type:               Feature/Change Request
 Package:            Feature/Change Request
 Operating System:   All
 PHP Version:        5.2.5
 Block user comment: N
 Private report:     N

 New Comment:

johannes, I haven't had a chance to test out ?: yet but someone else said that 
$val = $var['foo'] ?: ''; would still throw a notice if $var['foo'] was not set.

If that is true, then it would still be nice to have something like what is 
described here.


Previous Comments:
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[2007-11-10 21:38:29] johan...@php.net

PHP 6 has the "?:" operator ($result = $foo ?: $bar;) which is close to your 
request and which will most likely be merged back to 5.3.

------------------------------------------------------------------------
[2007-11-10 20:32:33] zyss at mail dot zp dot ua

Description:
------------
PHP programmers often need to check if certain variable is set when assigning 
its value to other variable or using it in expression. For example:

  $item_id = isset($_POST['item_id']) ? $_POST['item_id'] : null;

which is quite unreadable.

It would be much easier to write such things if there are function ifnset(mixed 
$value, mixed $alt) (If Not Set) which returns $value if $valus is set or $alt 
otherwise. Example above could be replaced with:

  $item_id = ifnset($_POST['item_id'], null);

or, if another function is added - ifset - which returns null if its argument 
is not set or not defined:

  $item_id = ifset($_POST['item_id']);

Similar function exists in MySQL 
(http://dev.mysql.com/doc/refman/5.1/en/control-flow-functions.html#function_ifnull)
 which makes life much easier when working with MySQL.

It is not possible to implement this function in PHP because when undefined or 
unset variable is passed as function argument PHP emits warning. Although 
warnings could be suppressed with @ it significantly slows down performance 
when such situation happens. Besides debugger catches all suppressed warnings 
anyway.

Thanks.



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