Edit report at https://bugs.php.net/bug.php?id=62207&edit=1
ID: 62207
Comment by: mail+php at requinix dot net
Reported by: mike dot mackintosh at angrystatic dot com
Summary: foreaching bindparam results in all params equaling
last value
Status: Open
Type: Bug
Package: PDO related
Operating System: Ubuntu 12.04 x86_64
PHP Version: 5.4.4RC2
Block user comment: N
Private report: N
New Comment:
Not a bug.
bindParam() works the value by-reference, which means you passed it a reference
to the $value variable. Not
its value at the time you called it. When the loop ends and you call query(),
$value will be whatever the
last one in the $array was: 1.
Use a reference to the item in the array:
$stmt2->bindParam($param, $array[$param]);
Previous Comments:
------------------------------------------------------------------------
[2012-06-01 14:39:11] mike dot mackintosh at angrystatic dot com
Description:
------------
I have noticed an issue when working with MySQL and PDO prepare statements. If
running a foreach on an array which contains the params for the prepare
statement, all params equal the value of the last param in the array.
See below.
Test script:
---------------
$pdo = new PDO('mysql:dbname=netsec_v2;host=localhost;', 'root', '');
$stmt = $pdo->prepare("CREATE TABLE BugTest
(
ID int NOT NULL AUTO_INCREMENT,
PRIMARY KEY(ID),
ColumnA varchar(15) NOT NULL,
ColumnB int NOT NULL
)");
$stmt->execute();
$array = array(":ColumnA" => "A", ":ColumnB" => 1);
$stmt2 = $pdo->prepare("INSERT INTO BugTest (ColumnA,ColumnB) VALUES (:ColumnA,
:ColumnB)");
foreach($array as $param => $value){
$stmt2->bindParam($param, $value);
}
$stmt2->execute();
$res = $pdo->query("SELECT * FROM BugTest")->fetchAll(PDO::FETCH_ASSOC);
var_dump($res);
Expected result:
----------------
ColumnA = A
ColumnB = 1
Actual result:
--------------
ColumnA = 1
ColumnB = 1
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=62207&edit=1
