Edit report at https://bugs.php.net/bug.php?id=61924&edit=1
ID: 61924 Updated by: larue...@php.net Reported by: jenwelsh at yahoo dot com Summary: cannot use self in interface function declaration Status: Feedback Type: Bug Package: Class/Object related PHP Version: 5.4.1 Assigned To: laruence Block user comment: N Private report: N New Comment: Actually, I think it's a improvement of PHP-5.4, this change is introduced by fixing this issue: https://bugs.php.net/bug.php?id=60573 before this, you declare class A implements IComparable{ public function equals(self $other){ return ($this->var == $other->var) ? 'equal' : 'different'; } } actullay the self in here is A, not IComparable. but in the IComparable, the self means IComparable itsself. In scrupulously, A is_a Icomparable, but not equal to Icomperable, what do you think? thanks Previous Comments: ------------------------------------------------------------------------ [2012-05-03 16:48:08] larue...@php.net Oh, sorry I misunderstanded , assign to my self , should have Sth to do with a fix made by me ------------------------------------------------------------------------ [2012-05-03 15:22:17] jenwelsh at yahoo dot com The reason I "think" it did work, is because it is **currently** working on a production site with PHP 5.3.11. And it **has** been working for over 2 years. ------------------------------------------------------------------------ [2012-05-03 14:52:08] larue...@php.net or you can change it to a feature request :) ------------------------------------------------------------------------ [2012-05-03 14:45:32] larue...@php.net it's always not allowed since php 5.2, why are you thinking it worked once? ------------------------------------------------------------------------ [2012-05-03 14:20:54] jenwelsh at yahoo dot com Description: ------------ I am reviewing existing code on a PHP5.4.1 testbed. I've discovered that interface declarations using 'self' as a type hint no longer allow implementations to use 'self' but require them to use the interface name. It is no longer possible for an interface to declare a method that requires the implementor's class as a typehint without declaring that class specifically. And that would limit the usefulness of that interface to one class only. Test script: --------------- interface IComparable { public function equals(self $other); } class A implements IComparable{ protected $var; public function __construct(self $v){ $this->var=$v; } public function equals($other){ return ($this->var == $other->var) ? 'equal' : 'different'; } } $a1= new A(7); $a2= new A(5); $a3= new A(5); echo $a1->equals($a2),"\n"; echo $a2->equals($a3),"\n"; Expected result: ---------------- different equal Actual result: -------------- PHP Fatal error: Declaration of A::equals() must be compatible with IComparable::equals(IComparable $other) ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=61924&edit=1
