Edit report at https://bugs.php.net/bug.php?id=60450&edit=1

 ID:                 60450
 Updated by:         cataphr...@php.net
 Reported by:        developer at elementica dot com
 Summary:            Looping in a copy of an array using foreach
                     by-reference change original array
-Status:             Open
+Status:             Bogus
 Type:               Bug
 Package:            Arrays related
 Operating System:   Linux, Windows
 PHP Version:        5.3.8
 Block user comment: N
 Private report:     N

 New Comment:

See 
http://nl.php.net/manual/en/language.references.whatdo.php#language.references.whatdo.assign
 near the end.

The work-around is unsetting the $elem variable after the last iteration when 
iterating by reference.


Previous Comments:
------------------------------------------------------------------------
[2011-12-06 10:05:23] developer at elementica dot com

Description:
------------
On a standard installation of PHP 5.3.x on many OSs (including Linux and 
Windows) we:
- set an array with at least two elements
- loop it using foreach by-reference changing each element
- create a copy of the array in another one using the "=" assignment
- loop on the copy as before
- we find the original array changed (usually or always: last element)

Example code given.

Documentation says "Array assignment always involves value copying. Use the 
reference operator to copy an array by reference." 

(http://php.net/manual/en/language.types.array.php).

It seems a problem of "foreach" used with the "by-reference" syntax.

Could be related to https://bugs.php.net/bug.php?id=8130 (subject appears to be 
the same, but here we have a foreach problem, while nothing is stated in #8130 
about it).

Test script:
---------------
$array1 = array(0 => 'zero', 1 => 'one');
foreach ($array1 as &$elem) { $elem .= ' (1)'; }; // NOTE: if we use $array1[0] 
.= ' (1)'; $array1[1] .= ' (1)'; no problem arises
$array2 = $array1;
foreach ($array2 as &$elem) { $elem .= ' (2)'; }; // NOTE: if we use $array2[0] 
.= ' (1)'; $array2[1] .= ' (1)'; the problem is still here, so first foreach 
seems to be the point
print_r ($array1);
// BUG! EXPECTED: array(0 => 'zero (1)', 1 => 'one (1)'), OUTPUT: array(0 => 
'zero (1)', 1 => 'one (1) (2)')

Expected result:
----------------
Array
(
    [0] => zero (1)
    [1] => one (1)
)

Actual result:
--------------
Array
(
    [0] => zero (1)
    [1] => one (1) (2)
)


------------------------------------------------------------------------



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