Edit report at https://bugs.php.net/bug.php?id=52982&edit=1
ID: 52982
Comment by: php dot net at kenman dot net
Reported by: php dot net at kenman dot net
Summary: Expose php_session_active to userland via new
function (patch included)
Status: Assigned
Type: Feature/Change Request
Package: Session related
PHP Version: 5.3.3
Assigned To: kalle
Block user comment: N
Private report: N
New Comment:
Any update on this?
Simple request; I'm not exactly sure what all Kalle was speaking to WRT "expose
the other values", but what I'm requested here is a tiny piece of
functionality,
and that is *all* that is being requested.
Previous Comments:
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[2010-10-05 07:34:11] php dot net at kenman dot net
pajoye,
I'm not sure if you understand which problem I'm trying to address here; it's
not whether or not session_start() was successful, it's whether or not there is
a current active session.
Many times, in frameworks or other large-scale applications, you have no way of
knowing whether session_start() has already been called. You cannot rely on
session_id(), SID, session_start(), $_SESSION, or any other session functions
or
session functionality (that I'm aware of) to tell me "yes, you already have a
session open" or "no, you do not have a session open" _before_ I call
session_start().
------------------------------------------------------------------------
[2010-10-04 12:15:56] paj...@php.net
The notice is documented and can be disabled using the display error settings.
To detect whether or not session_start was successful, you have to test its
return value (as of 5.3.0).
It is actually a documentation problem as the examples in the manual does not
check the return values (maybe add one on top of them using 5.3+).
------------------------------------------------------------------------
[2010-10-04 10:31:43] ka...@php.net
If we are going to expose php_session_active, we might aswell expose the other
values. I will cook up a patch and apply it to trunk shortly
------------------------------------------------------------------------
[2010-10-04 04:45:37] php dot net at kenman dot net
Description:
------------
Attempting to start a session after a session has already been started raises
an
E_NOTICE, however, there is no sane way to check if a session has already been
started. The only ways that I could devise were using the shut-up op (@) or by
creating wrapper functions around all of the session functions.
This is extreme because there exists in the PHP source, code which can do this;
my
patch exposes this code for userland comsumption.
More info:
http://stackoverflow.com/questions/3788369/how-to-tell-if-a-session-is-active
Test script:
---------------
session_start();
// 1000's of lines of code, which may/may not have closed the session
session_start(); // how to tell if a session is active here?
Expected result:
----------------
Should be able to ask PHP whether or not it knows of an active session.
Actual result:
--------------
Notice: A session had already been started - ignoring session_start()
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Edit this bug report at https://bugs.php.net/bug.php?id=52982&edit=1
