Edit report at http://bugs.php.net/bug.php?id=54438&edit=1
ID: 54438
Updated by: fel...@php.net
Reported by: michal dot brzuchalski at gmail dot com
Summary: use statement overwrite aliased namespace against
using multiple
Status: Bogus
Type: Feature/Change Request
Package: Class/Object related
Operating System: Linux
PHP Version: 5.3.6
Block user comment: N
Private report: N
New Comment:
There is parser error, you just need to use the right code to reproduce
it.
use A as Foo;
use B as Foo;
or
use A as Foo, B as Foo;
Previous Comments:
------------------------------------------------------------------------
[2011-04-02 20:11:15] michal dot brzuchalski at gmail dot com
So why there's no parse error if there can be more than one
class/namespace aliased ?
------------------------------------------------------------------------
[2011-04-02 19:06:09] fel...@php.net
This is not a bug. It works as expected, an alias cannot be used for
more than one class/namespace/...
------------------------------------------------------------------------
[2011-04-01 10:09:34] michal dot brzuchalski at gmail dot com
Description:
------------
In use statement we can use "," to separate aliased namespaces but the
alias only affect to the last one declared use namespace. It'll be
logical to use all declared namespaces in alias and use
classes/constants/closures/etc. from aliased namespace where they
exists.
Test script:
---------------
<?
namespace A;
class test1 {}
class test2 {}
namespace B;
class test1 {}
use A, B as Foo;
$test1 = new Foo\test1;
echo get_class($test1). "\n";
$test2 = new Foo\test2;
echo get_class($test2). "\n";
Expected result:
----------------
B\test1
A\test2
Actual result:
--------------
B\test1
PHP Fatal error: Class 'B\test2' not found in test.php on line 13
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/bug.php?id=54438&edit=1
