Edit report at http://bugs.php.net/bug.php?id=24949&edit=1
ID: 24949
Updated by: j...@php.net
Reported by: nickj-php at nickj dot org
Summary: Requesting nicer way of setting undefined variables
to default val. ifsetor / ?:
-Status: Open
+Status: Closed
Type: Feature/Change Request
-Package: Feature/Change Request
+Package: *General Issues
-Operating System: Any
+Operating System: *
-PHP Version: PHP6
+PHP Version: 6
-Assigned To:
+Assigned To: jani
Block user comment: N
Private report: N
New Comment:
?: exists since 5.3.
Previous Comments:
------------------------------------------------------------------------
[2006-01-20 01:46:25] nickj-php at nickj dot org
That workaround works for most situations, but maybe not all, such as
for constants (which cannot be passed-by-reference):
$val = _ifsetor(null, 'some value');
$php_ver = _ifsetor(PHP_VERSION, 'some value');
However, I'm not sure whether such a thing should ideally work (i.e.
perhaps it's best that this doesn't work, but on the other hand I can't
see why it shouldn't) - so I'm honestly not sure.
The main point though is that it's a common requirement, especially for
web forms, to have to test for a set value, and supply a default if none
is set - so it could be good if the language core natively included this
functionality.
Happily, it looks like this is going to happen in PHP6. Please see:
http://www.php.net/~derick/meeting-notes.html#ifsetor-as-replacement-for-foo-isset-foo-foo-something-else
(long URL, so may have wraparound issues).
The outcome was that PHP will get a new "?:" construct, like the one
mentioned previously by Xuefer. Personally, I realise now that this is a
far neater approach that having a function (such as
ifsetor/noUnset/default), so kudos to the PHP developers.
------------------------------------------------------------------------
[2006-01-19 19:03:01] chris dot vigelius at gmx dot net
Workaround: You can implement the functionality using references
error_reporting (E_ALL);
function _ifsetor(&$field, $defaultvalue) {
return (isset($field))?$field:$defaultvalue;
}
$v1 = $v2 = 'x';
echo _ifsetor($v1, 'v1 is not set');
unset($v2);
echo _ifsetor($v2, 'v2 is not set');
This works in 5.1.2 without warnings (haven't checked other versions,
though)
------------------------------------------------------------------------
[2005-01-02 02:42:02] nickj-php at nickj dot org
>From Derick Rethans PHP Look Back 2004
[http://www.derickrethans.nl/month-2004-12.php?item=20041231#20041231],
there were two discussions during the year on this topic on the PHP-DEV
mailing list, which I am adding links to here (as they help to summarize
various aspects of this) :
1) April 2004:
http://groups.google.com.au/groups?threadm=c5m94m$31k...@freebsd.csie.nctu.edu.tw
2) July 2004:
http://groups.google.com.au/groups?threadm=cci54b$t6...@freebsd.csie.nctu.edu.tw
------------------------------------------------------------------------
[2003-10-09 18:45:32] marcus at deck16 dot com
I also came across that "problem" and voted for that "bug".
It is possible to write a function though. Just pass the var Name as a
string:
<input type="text" name="Email" size="24" value="<?php echo
Set_Form_Value('Email'); ?>">
------------------------------------------------------------------------
[2003-08-22 12:00:36] xuefer at 21cn dot com
it would be nice to use "?:" operator as new c++ language
$a = isset($a) ? $a : "";
->
$a = $a ?: "";
$a = $a ?: $b ?: $c ?: $d;
better than:
$a = default($a, $b, $c, $d);
------------------------------------------------------------------------
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http://bugs.php.net/bug.php?id=24949
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