Edit report at http://bugs.php.net/bug.php?id=50394&edit=1

 ID:                 50394
 Comment by:         master33rd at yahoo dot com
 Reported by:        tstarling at wikimedia dot org
 Summary:            Reference argument converted to value in __call
 Status:             Closed
 Type:               Bug
 Package:            Scripting Engine problem
 Operating System:   Linux
 PHP Version:        5.3.1
 Assigned To:        pajoye
 Block user comment: N

 New Comment:

I find it disturbing that the bug has been declared fixed, when it
hasn't.



Starting Mediawiki with Xampp (even with the new beta of XAMPP)...the
same error occurs.  "PHP 5.3.1 is not compatible with MediaWiki due to a
bug involving reference parameters to __call. Upgrade to PHP 5.3.2 or
higher, or downgrade to PHP 5.3.0 to fix this. ABORTING (see
http://bugs.php.net/bug.php?id=50394 for details)"  Upgrading to PhP
5.3.3 doesn't fix the problem.  



Let's stop passing the buck and fix this.


Previous Comments:
------------------------------------------------------------------------
[2010-09-21 11:49:39] hugoniks at hotmail dot com

wtff

------------------------------------------------------------------------
[2010-09-20 05:14:07] tstarling at wikimedia dot org

heis: yes, the behaviour changed in 5.3.0. I'm not saying it was a good
idea, I'm just saying you should complain on some other bug report,
preferably one that I'm not CC'ed on. 



The correct way to pass reference arguments to functions via
call_user_func_array() hasn't changed, we've been doing it this way
since PHP 4. It's just that the impact of doing it the wrong way has
changed. Previously, the argument was silently converted to a value.
Now, a warning is shown and the function isn't called.

------------------------------------------------------------------------
[2010-09-19 10:54:53] heis dot turtlemad at gmail dot com

Please note that the "user code" we are talking about was running as
expected  until php5.3 was released; and that downgrading to 5.2 solves
the issue.



that means,  that the way to pass arrays as references in function args
has 

changed since the 5.3 release ?

------------------------------------------------------------------------
[2010-09-15 02:23:34] tstarling at wikimedia dot org

Commenters please note: you're receiving an error "parameter expected to
be a reference, value given", that does not mean that you are seeing
this bug. In fact, if you're using PHP 5.3.2 or later, it is pretty much
impossible for it to be this bug. 



Most cases of "parameter expected to be a reference, value given" are
due to bugs in the user code, not due to any problem with PHP. The
message indicates a mismatch between the reference/value status of
arguments to call_user_func_array() and the function declaration, as
in:



function foo( &$x ) {}

$x = '';

call_user_func_array( 'foo', array( $x ) );



The correct way to call the function foo() in this case is:



call_user_func_array( 'foo', array( &$x ) );



That is to say, the reference must be explicit in the array on the
calling side.

------------------------------------------------------------------------
[2010-09-15 01:16:45] jeremy at tuxmachine dot com

See bug 51174.

------------------------------------------------------------------------


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the rest of the comments, please view the bug report online at

    http://bugs.php.net/bug.php?id=50394


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