ID: 49832 Updated by: sjo...@php.net Reported By: marius dot andreiana at gmail dot com -Status: Open +Status: Bogus Bug Type: URL related Operating System: Linux PHP Version: 5.2.11 New Comment:
I don't think this is a bug. >From the documentation of parse_url: This function is not meant to validate the given URL, it only breaks it up into the above listed parts. Partial URLs are also accepted, parse_url() tries its best to parse them correctly. [...] On seriously malformed URLs, parse_url() may return FALSE and emit a E_WARNING. Previous Comments: ------------------------------------------------------------------------ [2009-10-10 18:44:42] marius dot andreiana at gmail dot com Indeed it's not valid. Therefore parse_url should return false, this is the bug. Now returns: Array ( [scheme] => http [host] => a.com:: ) Expected: return false ------------------------------------------------------------------------ [2009-10-10 18:06:50] sjo...@php.net Thank you for your bug report. Your example URL, "http://a.com:::";, does not seem valid to me. Why do you think this URL is valid? ------------------------------------------------------------------------ [2009-10-10 15:48:29] marius dot andreiana at gmail dot com Description: ------------ http://a.com::: Array ( [scheme] => http [host] => a.com:: ) expected: return false Reproduce code: --------------- $url_parts = parse_url("http://a.com:::";); print_r($url_parts); Expected result: ---------------- See Description Actual result: -------------- See Description ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=49832&edit=1
