ID:               47977
 Updated by:       sjo...@php.net
 Reported By:      fhgvbrdyftgjhgtfr at gazeta dot pl
-Status:           Open
+Status:           Feedback
 Bug Type:         PDO related
 Operating System: Unix
 PHP Version:      5.2.9
 New Comment:

Thank you for your bug report.

Although you supplied code to reproduce the problem, it is more
complicated and longer than necessary. Please supply a short, complete
and understandable piece of code to reproduce the problem. This is to
make sure the problem is with PHP and not with the example.


Previous Comments:
------------------------------------------------------------------------

[2009-05-16 01:20:50] fhgvbrdyftgjhgtfr at gazeta dot pl

<?php
$db = new PDO('mysql:dbname=test;host=localhost', 'root', '');
$array2 = array('gb', 'us', 'nz', 'fr', 'de');
$array3 = array('fr'=>true, 'de'=>true);
$array = array_diff($array2, array_keys($array3));
reset($array);
$size = count($array);
$in = '?';
for($i = 1; $i < $size; ++$i) $in .= ', ?';
$stmt = $db->prepare('SELECT `name` FROM `table` WHERE `language` = ?
AND `code` IN('.$in.')');
$stmt->bindValue(1, 'en', PDO::PARAM_STR);
$i = 1;
$element = current($array);
do {
        $stmt->bindParam(++$i, $element, PDO::PARAM_STR);
} while(($element = next($array)) !== false);
$stmt->execute();
var_dump($stmt->fetchAll());
?>
-----------------
expected result:
array(3) {
  [0]=>
  array(2) {
    ["name"]=>
    string(4) "test"
    [0]=>
    string(4) "test"
  }
  [1]=>
  array(2) {
    ["name"]=>
    string(4) "test"
    [0]=>
    string(4) "test"
  }
  [2]=>
  array(2) {
    ["name"]=>
    string(4) "test"
    [0]=>
    string(4) "test"
  }
}
--------------------
actual result:
array(0) {
}
--------------------
db:
CREATE TABLE IF NOT EXISTS `table` (
  `name` varchar(45) NOT NULL,
  `language` enum('en','fr') NOT NULL,
  `code` char(2) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;


INSERT INTO `table` (`name`, `language`, `code`) VALUES
('test', 'en', 'gb'),
('test', 'en', 'nz'),
('test', 'en', 'us'),
('test', 'en', 'cz');

------------------------------------------------------------------------

[2009-05-08 01:00:02] php-bugs at lists dot php dot net

No feedback was provided for this bug for over a week, so it is
being suspended automatically. If you are able to provide the
information that was originally requested, please do so and change
the status of the bug back to "Open".

------------------------------------------------------------------------

[2009-04-30 10:47:04] j...@php.net

Thank you for this bug report. To properly diagnose the problem, we
need a short but complete example script to be able to reproduce
this bug ourselves. 

A proper reproducing script starts with <?php and ends with ?>,
is max. 10-20 lines long and does not require any external 
resources such as databases, etc. If the script requires a 
database to demonstrate the issue, please make sure it creates 
all necessary tables, stored procedures etc.

Please avoid embedding huge scripts into the report.



------------------------------------------------------------------------

[2009-04-16 00:22:47] fhgvbrdyftgjhgtfr at gazeta dot pl

Description:
------------
bindParam doesn't work with vars returned by current(), next()

Reproduce code:
---------------
<?php
$array = array_diff($array2, array_keys($array3));
reset($array);
$size = count($array);
$in = '?';
for($i = 1; $i < $size; ++$i) $in .= ', ?';
$stmt = $db->prepare('SELECT `name` FROM `table` WHERE `language` = ?
AND `code` IN('.$in.')');
$stmt->bindValue(1, 'en', PDO::PARAM_STR, 2);
$i = 1;
$element = current($array);
do {
        $stmt->bindParam(++$i, $element, PDO::PARAM_STR, 2);
} while(($element = next($array)) !== false);

Expected result:
----------------
SELECT `name` FROM `table` WHERE `language` = 'en' AND `code` IN('us',
'gb', 'nz')

Actual result:
--------------
SELECT `name` FROM `table` WHERE `language` = 'en' AND `code` IN('0',
'0', '0')

When i change
$stmt->bindParam(++$i, $element, PDO::PARAM_STR, 2);
to
$stmt->bindValue(++$i, $element, PDO::PARAM_STR, 2);
i get:
SELECT `name` FROM `table` WHERE `language` = 'en' AND `code` IN('us',
'gb', 'nz')


------------------------------------------------------------------------


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