ID: 42384 Updated by: [EMAIL PROTECTED] Reported By: jw at coffeecup dot com -Status: Open +Status: Bogus Bug Type: Scripting Engine problem Operating System: OS X PHP Version: 5.2.3 New Comment:
Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php The value created by (array)$arr is a temporary variable which can't be referenced. Previous Comments: ------------------------------------------------------------------------ [2007-08-22 16:21:55] jw at coffeecup dot com Description: ------------ I get a syntax error when I cast the array_expression portion of a foreach loop to an array while using the & operator on the value portion. Reproduce code: --------------- $arr = array(1, 2, 3, 4); foreach ((array)$arr as &$value) { $value = $value * 2; } print_r($arr); Expected result: ---------------- Array ( [0] => 2 [1] => 4 [2] => 6 [3] => 8 ) Actual result: -------------- Parse error: syntax error, unexpected '&', expecting T_STRING or T_VARIABLE or '$' ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=42384&edit=1
