>I'm loosing my hair on coordinates conversion and image extraction.
>
>Here is what I'm trying to do :
>
>I want to perform keyword search on non-searchable pdf or pdfs where
>text layer is not well positioned behind images (and then underline the
>results using annots) using PDFBOX and an OCR:
>
>I've extended printImageLocation  the following way :
>On a given page I extract all images and generate png images with JAI
>for better quality (tried getting a sole image for the whole page but
>results are not good enough with the OCR due to layout issues I think,
>with JAI I expect to be able to posterize, reduce noise if necessary,
>etc...to make the ocr happy).
>I externally run an ocr on them (ocropus/tesseract. it's c++, so I have
>some "Process p = Runtime.getRuntime().exec(cmd); " code) which
>produces  hOCR files giving  text and coordinates for each characters. I'm 
>then able to determine the coordinates of  a keyword parsing the
>hOCR file.
>At this point, I have the coordinates of the keyword in the image, the
>position of the image on the page and the size of the image.
>I then try to "translate to" coordinates in the pdf page from the ones I
>have got from the parsed image.
>First I invert the bounding box as the OCR gives me a UpperLeft/
>LowerRight couple of points.
>then ...I'm stucked : I expected the origin to be lowerleft in a pdf
>page but it seems to be upperLeft here.
>and to be honest, I hardly figure out which corner of the image is used
>to determine its location and what is the metric used.
>Inside the image, I retrieve coordinates in dot.
>
>For example, here are the images I've found :
>[I0] at 571.26746,71.80139 size=796.0658,93.23215 (small logo) [I1] at 
>368.0984,85.12024 size=92.90973,196.4537 (small logo) [I2] at 
>583.11694,707.5416 size=12841.42,15587.612 (the scanned article) [I3] at 
>176.53192,341.2494 size=402.6675,1046.7035 (image attached to
>the article)
>
>visually, [I0] is upperLeft, [I1] is at [I0] right side, [I3] is upper
>right but below [I0] and i1 line.
>[I2] is the "body" of the page actually a press article, where I find
>the keyword's occurences.
>
>here is a set of coordinates retrieved from the ocr processing (upper
>left / lower right):
>keyword: (2056.0/2484.0) (2193.0/2501.0)
>
>which gives (lower left / upper right):
>(2056.0/2501.0) (2193.0/2484.0)
>
>here are the coordinates of the same occurence in the pdf (the result I
>would find after a conversion lowerleft / upper right.  Provided here
>parsing the text layer hopefully well positionned) :
>START : String[ xy=511.5022,665.7338 fontsize=33.0 xscale=0.24686399
>yscale=0.225744 height=5.579715 space=2.2647307 width=128.40302] = keyword END 
>: String[ xy=511.5022,665.7338 fontsize=33.0 xscale=0.24686399
>yscale=0.225744 height=5.579715 space=2.2647307 width=128.40302] = keyword
>--------->keyword   : 1790.4882,2322.2808, 1881.345,2348.561 (the
>bounding box converted in a suitable metric system to put annotations on it)
>
>I guess I have to set up a transformation matrix but I don't know what
>parameters I have to take into accounts (and if they are available in a
>way or another !).
>Could someone provide some advices ?

I don't understand every point of your problem, but here are some details you 
are perhaps looking for:

- the pdf-0,0 reference is the lower left corner (as you already mentioned)
- a possible dimension of a page is something like this: 612, 792 (Letter) or 
596, 843 (DINA4) both portrait
- images are drawn starting at their lower left corner, with the given width 
and height in the pdf
- the image may be stored in the pdf-document with a larger/smaller dimension 
than used for displaying/printing

If you want to compare your ocr-results with the pdf, you have to have a look 
at the possible scaling of the image.

HTH,
Andreas

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