On Wed 12 Aug 2009 at 20:11:47 -0700, walt wrote: > Now, that last line begins with 'E', so uudeview figures that this line > of code should contain (69-32)*4/3 characters, which is 49.3. It then > reads the next 49 chars from that line and proceeds to uudecode them, > even though it produces garbage.
An easy check is to see if the line has the correct number of characters on it. In fact it may have one more: some versions of uuencode add an extra checksum character at the end of the line. But then it should match, of course. And fractional numbers of characters are not possible :) -Olaf. -- ___ Olaf 'Rhialto' Seibert -- You author it, and I'll reader it. \X/ rhialto/at/xs4all.nl -- Cetero censeo "authored" delendum esse. _______________________________________________ Pan-users mailing list Pan-users@nongnu.org http://lists.nongnu.org/mailman/listinfo/pan-users
