Each time this code is executed, a new sequence is created with the same
name, and so the method always returns 1 as next number. Why?
public long next( String seqName ) {
OSequenceLibrary sequenceLibrary = access.graph
.getRawGraph().getMetadata().getSequenceLibrary();
OSequence seq = sequenceLibrary.getSequence( seqName );
if( seq == null ) {
seq = sequenceLibrary.createSequence(seqName, SEQUENCE_TYPE.ORDERED, new
OSequence.CreateParams().setStart(0L));
}
return seq.next();
}
I'm using graphdb v.2.2.13
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