Hi, yes even if you incorporate the kilo=1024 example: I filled in the example below on the site: RAID Mode: z1 Disk Size: 3 tb Quantity of Disks: 10
RAID-Z *Raw Storage: 30.0 TB / 30000.0 GB *Usable Storage: 24.6 TB / 25145.7 GB RAID-Z uses one disk for Parity much like RAID5 and requires at least three drives to be used. *Usable storage is the actual post-format amount where kilo = 1024, not 1000 If I use the (n-1)formula this would amount to: (10-1) * 3 TB = 27 TB (27000 GB) even if you use 1 TB=1024 GB: (10-1) * 3072 GB = 27.648 GB Somewhere theres about 2.5 TB being used for something in their calculations. Maybe someone can explain or show me where my calculation is going wrong? Thanx R > Date: Tue, 8 Apr 2014 16:32:23 +0200 > From: [email protected] > To: [email protected] > Subject: Re: [OpenIndiana-discuss] Formula raidz storage space caclulation > > Hi, > > "Randy S" <[email protected]> írta 2014-04-08 16:16-kor: > > The information that I have about the formula to use is (n-1) x storage > > space per disk > > n=number of disks > > 1=is de disk used for parity in a raidz1 configuration. > > In the case of Raidz2 , this number would be 2 (n-2) x space. > > > > My question is: is this formula correct? > > Reason, my outcome always differs with from the outcome on the following > > website: http://www.servethehome.com/raid-calculator/ > > What would be the correct formula to use? > > Did you count in your calculations what the manufacturers cheat on the > meaning of kilo (1024 vs 1000)? > They also note that: > " > *Usable storage is the actual post-format amount where kilo = 1024, not > 1000 > " > > Regards, > György > > _______________________________________________ > OpenIndiana-discuss mailing list > [email protected] > http://openindiana.org/mailman/listinfo/openindiana-discuss _______________________________________________ OpenIndiana-discuss mailing list [email protected] http://openindiana.org/mailman/listinfo/openindiana-discuss
