> Date: Wed, 26 Oct 2016 09:05:41 -0400 > From: Matthew Harrigan <harrigan.matt...@gmail.com> > > np.cumsum(np.diff(x, to_begin=x.take([0], axis=axis), axis=axis), axis=axis) > > That's certainly not going to win any beauty contests. The 1d case is > clean though: > > np.cumsum(np.diff(x, to_begin=x[0])) > > I'm not sure if this means the API should change, and if so how. Higher > dimensional arrays seem to just have extra complexity. > >> >> I like the proposal, though I suspect that making it general has >> obscured that the most common use-case for padding is to make the >> inverse of np.cumsum (at least that?s what I frequently need), and now >> in the multidimensional case you have the somewhat unwieldy: >> >> >>> np.diff(a, axis=axis, to_begin=np.take(a, 0, axis=axis)) >> >> rather than >> >> >>> np.diff(a, axis=axis, keep_left=True) >> >> which of course could just be an option upon what you already have. >>
So my suggestion was intended that you might want an additional keyword argument (keep_left=False) to make the inverse np.cumsum use-case easier, i.e. you would have something in your np.diff like: if keep_left: if to_begin is None: to_begin = np.take(a, [0], axis=axis) else: raise ValueError(‘np.diff(a, keep_left=False, to_begin=None) can be used with either keep_left or to_begin, but not both.’) Generally I try to avoid optional keyword argument overlap, but in this case it is probably justified. Peter _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org https://mail.scipy.org/mailman/listinfo/numpy-discussion