On Mon, May 16, 2016 at 12:24 PM, Elliot Hallmark <permafact...@gmail.com> wrote:
> Use `random.shuffle(range(len(arr))` to make a list of indices. Use a > slices to get your 20/80. Convert to integer arrays and index your > original array with them. Use sorted on the 80% list if you need to > preserve the order. > similar but simpler You can just random permute/shuffle an array with 20% ones (True) and 80% zeros (False) and use it as a mask to select from the original array. Josef > > > -Elliot > > On Mon, May 16, 2016 at 11:04 AM, Martin Noblia < > martin.nob...@openmailbox.org> wrote: > >> I think with `np.random.choice` >> >> >> http://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.random.choice.html >> >> >> On 05/16/2016 11:08 AM, Florian Lindner wrote: >> >> Hello, >> >> I have an array of shape (n, 2) from which I want to extract a random sample >> of 20% of rows. The choosen samples should be removed the original array and >> moved to a new array of the same shape (n, 2). >> >> What is the most clever way to do with numpy? >> >> Thanks, >> Florian >> _______________________________________________ >> NumPy-Discussion mailing >> listNumPy-Discussion@scipy.orghttps://mail.scipy.org/mailman/listinfo/numpy-discussion >> >> >> -- >> *Martin Noblia* >> >> _______________________________________________ >> NumPy-Discussion mailing list >> NumPy-Discussion@scipy.org >> https://mail.scipy.org/mailman/listinfo/numpy-discussion >> >> > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > https://mail.scipy.org/mailman/listinfo/numpy-discussion > >
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