On Di, 2016-02-23 at 11:45 -0500, Benjamin Root wrote:
> but, it isn't really ambiguous, is it? The -1 can only refer to a
> single dimension, and if you ignore the zeros in the original and new
> shape, the -1 is easily solvable, right?

I think if there is a simple logic (like using 1 for all zeros in both
input and output shape for the -1 calculation), maybe we could do it. I
would like someone to think about it carefully that it would not also
allow some unexpected generalizations. And at least I am getting a
BrainOutOfResourcesError right now trying to figure that out :).

- Sebastian


> Ben Root
> 
> On Tue, Feb 23, 2016 at 11:41 AM, Warren Weckesser <
> warren.weckes...@gmail.com> wrote:
> > 
> > 
> > On Tue, Feb 23, 2016 at 11:32 AM, Benjamin Root <
> > ben.v.r...@gmail.com> wrote:
> > > Not exactly sure if this should be a bug or not. This came up in
> > > a fairly general function of mine to process satellite data.
> > > Unexpectedly, one of the satellite files had no scans in it,
> > > triggering an exception when I tried to reshape the data from it.
> > > 
> > > >>> import numpy as np
> > > >>> a = np.zeros((0, 5*64))
> > > >>> a.shape
> > > (0, 320)
> > > >>> a.shape = (0, 5, 64)
> > > >>> a.shape
> > > (0, 5, 64)
> > > >>> a.shape = (0, 5*64)
> > > >>> a.shape = (0, 5, -1)
> > > Traceback (most recent call last):
> > >   File "<stdin>", line 1, in <module>
> > > ValueError: total size of new array must be unchanged
> > > 
> > > So, if I know all of the dimensions, I can reshape just fine. But
> > > if I wanted to use the nifty -1 semantic, it completely falls
> > > apart. I can see arguments going either way for whether this is a
> > > bug or not.
> > > 
> > 
> > When you try `a.shape = (0, 5, -1)`, the size of the third
> > dimension is ambiguous.  From the Zen of Python:  "In the face of
> > ambiguity, refuse the temptation to guess."
> > 
> > Warren
> > 
> > 
> > 
> > > 
> > > Thoughts?
> > > 
> > > Ben Root
> > > 
> > > _______________________________________________
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> > > 
> > 
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