|
I am trying to
understand how nditer(ops, order='K') handles C and F order. In
the documentation it states
"‘K’ means as close to the order the array elements appear in memory as possible" but I seem to be getting inconsistent results (numpy 1.9): >>> a = np.array([[1, 2], [3, 4]], order="C") >>> b = np.array([[1, 2], [3, 4]], order="F") >>> [v for v in np.nditer([a], order='K')] [array(1), array(2), array(3), array(4)] >>> [v for v in np.nditer([b], order='K')] [array(1), array(3), array(2), array(4)] >>> [v for v in np.nditer([a,b], order='K')] [(array(1), array(1)), (array(2), array(2)), (array(3), array(3)), (array(4), array(4))] The result for np.nditer([b], order='K') seems to be wrong. Could someone confirm this is an issue or explain what is going on? Matti |
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