On 11/13/2014 1:19 AM, Antony Lee wrote: > "t.__bool__()" also returns True
But t.__nonzero__() is being called in the `if` test. The question is: is the difference between `__nonzero__` and `__bool__` intentional. By the way, there has been a change in behavior. For example, in 1.7.1 if you call `t.__bool__()` it raised an attribute error -- unless one first called `t.__nonzero__()` and then called `t.__bool__()`, which was of course very weird and needed to be fixed. Maybe (?) not like this. In fact the oddity probably remains but moved. in 1.9.0 I see this: >>> np.__version__ '1.9.0' >>> t = np.array(None); t[()] = np.array([None, None]) >>> t.__nonzero__() Traceback (most recent call last): File "<stdin>", line 1, in <module> AttributeError: 'numpy.ndarray' object has no attribute '__nonzero__' >>> t.__bool__() True >>> t.__nonzero__() ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() Alan Isaac _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
