On Sat, Oct 18, 2014 at 9:00 PM, Artur Bercik <vbubbl...@gmail.com> wrote:
> > > On Sat, Oct 18, 2014 at 8:28 PM, Julian Taylor < > jtaylor.deb...@googlemail.com> wrote: > >> On 18.10.2014 07:58, Artur Bercik wrote: >> > Dear Python and Numpy Users: >> > >> > My data are in the form of '32-bit unsigned integer' as follows: >> > >> > myData = np.array([1073741824, 1073741877, 1073742657, 1073742709, >> > 1073742723, 1073755137, 1073755189,1073755969],dtype=np.int32) >> > >> > I want to get the index of my data where the following occurs: >> > >> > Bit No. 0–1 >> > Bit Combination: 00 >> > >> > How can I do it? I heard this type of problem first time, please help >> me. >> > >> > Artur >> > >> >> not sure I understand the problem, maybe this? >> >> np.where((myData & 0x3) == 0) >> > > yes, it works greatly for the following case: > > myData = np.array([1073741824, 1073741877, 1073742657, 1073742709, > 1073742723, 1073755137, 1073755189,1073755969],dtype=np.uint32) > Bit No. 0–1 > Bit Combination: 00 > > Can you make such automation for the following case as well? > > Bit No. 2–5 > Bit Combination: 1101 > > Thanks in the advance. > Also wondering why np.where((myData & 0x3) == 0) instead of just np.where((myData & 3) == 0) > > > > > >> >> _______________________________________________ >> NumPy-Discussion mailing list >> NumPy-Discussion@scipy.org >> http://mail.scipy.org/mailman/listinfo/numpy-discussion >> > >
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