Hi,
On Tue, Jan 21, 2014 at 8:34 AM, Dr. Leo <fhaxbo...@googlemail.com> wrote: > Hi, > > I would like to write something like: > > In [25]: iterable=((i, i**2) for i in range(10)) > > In [26]: a=np.fromiter(iterable, int32) > --------------------------------------------------------------------------- > ValueError Traceback (most recent call > last) > <ipython-input-26-5bcc2e94dbca> in <module>() > ----> 1 a=np.fromiter(iterable, int32) > > ValueError: setting an array element with a sequence. > > > Is there an efficient way to do this? > Perhaps you could just utilize structured arrays ( http://docs.scipy.org/doc/numpy/user/basics.rec.html), like: iterable= ((i, i**2) for i in range(10)) a= np.fromiter(iterable, [('a', int32), ('b', int32)], 10) a.view(int32).reshape(-1, 2) Out[]: array([[ 0, 0], [ 1, 1], [ 2, 4], [ 3, 9], [ 4, 16], [ 5, 25], [ 6, 36], [ 7, 49], [ 8, 64], [ 9, 81]]) My 2 cents, -eat > > Creating two 1-dimensional arrays first is costly as one has to > iterate twice over the data. So the only way I see is creating an > empty [10,2] array and filling it row by row. This is memory-efficient > but slow. List comprehension is vice versa. > > If there is no solution, wouldn't it be possible to rewrite fromiter > so as to accept sequences? > > Leo > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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