Hi, I'm trying to increment an array using indexing and a second array for increment values (since it might be a little tedious to explain, see below for a short example).
Using "direct" indexing, the values in the example are incremented by 1 only while I want to achieve the alternative behavior. My question is whether there is such function in numpy or if there a re better way to achieve the same result ? (I would like to avoid the while statement) I found and adapted the alternative solution from: http://stackoverflow.com/questions/2004364/increment-numpy-array-with-repeated-indices but it is only for a fixed increment from what I've understood. Nicolas # ------------------------ import numpy as np n,p = 5,100 nodes = np.zeros( n, [('value', 'f4', 1)] ) links = np.zeros( p, [('source', 'i4', 1), ('target', 'i4', 1)]) links['source'] = np.random.randint(0, n, p) links['target'] = np.random.randint(0, n, p) targets = links['target'] # Indices can be repeated K = np.ones(len(targets)) # Note K could be anything # Direct indexing nodes['value'] = 0 nodes['value'][targets] += K print nodes # "Alternative" indexing nodes['value'] = 0 B = np.bincount(targets) while B.any(): I = np.argwhere(B>=1) nodes['value'][I] += K[I] B = np.maximum(B-1,0) print nodes _______________________________________________ NumPy-Discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
