Hi, On Sun, Sep 9, 2012 at 12:56 AM, nicky van foreest <vanfore...@gmail.com>wrote:
> Hi, > > I ran the following code: > > args = np.array([4,8]) > print np.sum( (arg > 0) for arg in args) > print np.sum([(arg > 0) for arg in args]) > print np.prod( (arg > 0) for arg in args) > print np.prod([(arg > 0) for arg in args]) > Can't see why someone would write code like above, but anyway: In []: args = np.array([4,8]) In []: print np.sum( (arg > 0) for arg in args) 2 In []: print np.sum([(arg > 0) for arg in args]) 2 In []: print np.prod( (arg > 0) for arg in args) <generator object <genexpr> at 0x062BDA08> In []: print np.prod([(arg > 0) for arg in args]) 1 In []: print np.prod( (arg > 0) for arg in args).next() True In []: sys.version Out[]: '2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)]' In []: np.version.version Out[]: '1.6.0' My 2 cents, -eat > > with this result: > > 2 > 1 > <generator object <genexpr> at 0x1c70410> > 1 > > Is the difference between prod and sum intentional? I would expect > that numpy.prod would also work on a generator, just like numpy.sum. > > BTW: the last line does what I need: the product over the truth values > of all elements of args. Is there perhaps a nicer (conciser) way to > achieve this? Thanks. > > Nicky > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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