Dear all, I have a two-dimensional array:
a = array([[1,2,3],[0,2,1],[5,7,8]]) I want to reorder it by the last column in descending order, so that I get: b =array([[5, 7, 8],[1, 2, 3],[0, 2, 1]]) What I did first is the following, which reorders the array in ascending order (I found that method in the internet): b = array(sorted(a, key=lambda new_entry: new_entry[2])) b = array([[0, 2, 1],[1, 2, 3],[5, 7, 8]]) But I want it just the other way arround. So I did the following afterwards which results in an array only containing zeros: b_indices = b.argsort() b_matrix = b[b_indices[::-1]] new_b = b_matrix[len(b_matrix)-1] Is there an easy way to reorder it? Or is there at least a complicated way which produces the right output? I hope you can help me! Thanks! Best regards, Nicole _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
