On Mon, Mar 5, 2012 at 11:14 AM, Neal Becker <ndbeck...@gmail.com> wrote:
> What is a simple, efficient way to determine if all elements in an array (in 
> my
> case, 1D) are equal?  How about close?

For the exactly equal case, how about:

I[1] a = np.array([1,1,1,1])
I[2] np.unique(a).size
O[2] 1    # All equal

I[3] a = np.array([1,1,1,2])
I[4] np.unique(a).size
O[4] 2   # All not equal
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