Sorry, I copy and pasted the wrong example r result - it should be as you say: r = array([ 1, 1, 1, 48, 68, 1, 75, 1, 1, 115, 1, 95, 1, 1, 1, 1, 1, 1, 1, 28, 1, 68, 1, 1, 28])
The reason for looking for an alternative solution is performance as the sizes of r, s and c are very large with the for-loop calculation repeated continuously (with different r, s and c). From: eat Sent: Saturday, February 11, 2012 3:12 PM To: Discussion of Numerical Python Subject: Re: [Numpy-discussion] Want to eliminate direct for-loop Hi, On Sat, Feb 11, 2012 at 10:56 PM, Dinesh B Vadhia <dineshbvad...@hotmail.com> wrote: Could the following be written without the direct for-loop? import numpy # numpy vector r of any data type and length, eg. r = numpy.ones(25, dtype='int') # s is a list of values (of any data type), eg. s = [47, 27, 67] # c is a list of (variable length) lists where the sub-list elements are index values of r and len(s) = len(c), eg. c = [[3, 6, 9], [6, 11, 19, 24], [4, 9, 11, 21 ]] # for each element in each sub-list c, add corresponding s value to the index value in r, eg. for i, j in enumerate(c): r[j] += s[i] So, we get: r[[3, 6, 9]] += s[0] = 1 + 47 = 48 r[[6, 11, 19, 24]] += s[1] = 1 + 27 = 28 r[[4, 9, 11, 21]] += s[2] = 1 + 67 = 68 ie. r = array([ 1, 1, 1, 95, 68, 1, 122, 1, 1, 162, 1, 95, 1, 1, 1, 1, 1, 1, 1, 28, 1, 68, 1, 1, 28]) Thank-you! Could you describe more detailed manner about why you want to get rid of that loop? Performance wise? If so, do you have profiled what's the bottleneck? Please provide also a more detailed description of your problem, since now your current spec seems to yield: r= array([ 1, 1, 1, 48, 68, 1, 75, 1, 1, 115, 1, 95, 1, 1, 1, 1, 1, 1, 1, 28, 1, 68, 1, 1, 28]) My 2 cents, -eat _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
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