Hi, If I remember correctly, float is a double (precision float). The precision is more important in doubles (float64) than in usual floats (float32). And 20091231 can not be reprensented in 32bits floats.
Matthieu 2011/12/17 Alex van Houten <sparrow2...@yahoo.com> > Try this: > $ python > Python 2.7.1 (r271:86832, Apr 12 2011, 16:15:16) > [GCC 4.6.0 20110331 (Red Hat 4.6.0-2)] on linux2 > Type "help", "copyright", "credits" or "license" for more information. > >>> import numpy as np > >>> np.__version__ > '1.5.1' > >>> time=[] > >>> time.append(20091231) > >>> time_array=np.array(time,'f') > >>> time_array > array([ 20091232.], dtype=float32) > 20091231--->20091232 Why? > Note: > >>> float(20091231) > 20091231.0 > Thanks, > Alex. > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion > > -- Information System Engineer, Ph.D. Blog: http://matt.eifelle.com LinkedIn: http://www.linkedin.com/in/matthieubrucher
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