On Thu, Jun 9, 2011 at 6:28 PM, Robert Kern <[email protected]> wrote:
> On Thu, Jun 9, 2011 at 16:27, Robert Kern <[email protected]> wrote: > > On Thu, Jun 9, 2011 at 15:01, Mark Wiebe <[email protected]> wrote: > >> I've replaced the previous two pull requests with a single pull request > >> rolling up all the changes so far. The newest changes include finishing > the > >> generic unit and np.arange function support. > >> https://github.com/numpy/numpy/pull/87 > >> Because of the nature of datetime and timedelta, arange has to be > slightly > >> different than with all the other types. In particular, for datetime the > >> primary signature is np.arange(datetime, datetime, timedelta). > >> I've implemented a simple extension which allows for another way to > specify > >> a date range, as np.arange(datetime, timedelta, timedelta). Here (start, > >> delta) represents the datetime range [start, start+delta). Some > examples: > >>>>> np.arange('2011', '2020', dtype='M8[Y]') > >> array(['2011', '2012', '2013', '2014', '2015', '2016', '2017', '2018', > >> '2019'], dtype='datetime64[Y]') > >>>>> np.arange('today', 10, 3, dtype='M8') > >> array(['2011-06-09', '2011-06-12', '2011-06-15', '2011-06-18'], > >> dtype='datetime64[D]') > > > > I would prefer that we not further overload the signature of > > np.arange() for this case. A new function dtrange() that can take a > > delta would be preferable. > > Alternately, a general np.deltarange(start, delta[, step]) +1 function > might be useful, too. I know I've done the following quite a few > times, even with just integers: > > np.arange(start, start+delta) > I like this approach. -Mark > -- > Robert Kern > > "I have come to believe that the whole world is an enigma, a harmless > enigma that is made terrible by our own mad attempt to interpret it as > though it had an underlying truth." > -- Umberto Eco > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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