On Wed, Jun 1, 2011 at 9:35 PM, David Cournapeau <[email protected]> wrote:
> On Thu, Jun 2, 2011 at 1:49 AM, Mark Miller <[email protected]> wrote:
>> Not quite. Bincount is fine if you have a set of approximately
>> sequential numbers. But if you don't....
>
> Even worse, it fails miserably if you sequential numbers but with a high 
> shift.
>
> np.bincount([100000001, 100000002]) # will take a lof of memory
>
> Doing bincount with dict is faster in those cases.

same with negative numbers, but in these cases I just subtract the min
and we are back to the fast bincount case

cheers,

Josef

>
> cheers,
>
> David
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