Thank you very much Stéfan!!
2011/5/24 Stéfan van der Walt <[email protected]> > Hi Chris > > On Tue, May 24, 2011 at 9:29 AM, Goo Creations <[email protected]> > wrote: > > At this point I'm stuck, since I'm not sure how to do the row based > > transform on ownRes. > > Is there anyone out there who knows how to do this? > > NumPy's FFT supports an "axis" argument, so you can do > > In [29]: own = np.array([[1+0j, 2+0j], [3+0j, 4+0j]]) > > In [30]: fft_step1 = np.fft.fft(own, axis=0) > > In [31]: fft_step2 = np.fft.fft(fft_step1, axis=1) > > In [32]: fft_step2 > Out[32]: > array([[ 10.+0.j, -2.+0.j], > [ -4.+0.j, 0.+0.j]]) > > In [33]: np.fft.fft2(own) > Out[33]: > array([[ 10.+0.j, -2.+0.j], > [ -4.+0.j, 0.+0.j]]) > > Cheers > Stéfan > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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