Yeah, there were no previous installs.

Well, I removed the pip installed numpy and did a python setup.py
install and all works now.

Really bizarre, I didn't think pip did much outside of the standard
python setup.py install, other that some more automation.

Thanks for the help.

Ilya

On Sun, May 30, 2010 at 5:15 PM, Charles R Harris
<charlesr.har...@gmail.com> wrote:
>
>
> On Sun, May 30, 2010 at 2:22 PM, Ilya Sterin <ster...@gmail.com> wrote:
>>
>> Numpy 1.4.1.  I built it myself.
>>
>> The version of numpy in question on CentOS was built against a 2.6.5
>> version of python 64 bit binary and built/installed with pip.
>>
>> The version which is working on my OS X is a universal binary and both
>> python and numpy are built as such.  I'm running python in 64bit mode
>> though and all works fine there.
>>
>> I just tried to install numpy as per yum instructions on numpy site
>> with the default Centos python 2.4.  It installed numpy 1.2 and the
>> determinant function works there.
>>
>> I need to get this to work with 2.6 though, as my app relies on it.  Any
>> ideas?
>>
>> Thanks.
>>
>
> It works fine for me on 2.6, which is why I asked for more details.
>
> $[char...@ubuntu ~]$ python
> Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41)
> [GCC 4.4.3] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> import numpy
>>>> numpy.linalg.det(numpy.array([[1, 2], [3, 4]]))
> -2.0
>>>> numpy.__version__
> '1.4.1'
>
> Did you remove the previous installation of numpy, if any? And why not do
> the usual "sudo python setup.py install"  thingie instead of pip?
>
> Chuck
>
>
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