On Sat, Apr 10, 2010 at 7:31 PM, Charles R Harris <[email protected] > wrote:
> > > On Sat, Apr 10, 2010 at 6:17 PM, Gökhan Sever <[email protected]>wrote: > >> Hello, >> >> Is there a simpler way to get "c" from "a" >> >> I[1]: a = np.arange(10) >> >> I[2]: b = a[3:] >> >> I[3]: b >> O[3]: array([3, 4, 5, 6, 7, 8, 9]) >> >> I[4]: c = np.insert(b, [7]*3, 0) >> O[5]: array([3, 4, 5, 6, 7, 8, 9, 0, 0, 0]) >> >> a and c have to be same in length and the left shift must be balanced with >> equal number of 0's >> >> > Maybe something like > > In [1]: a = np.arange(10) > > In [2]: b = zeros_like(a) > > In [3]: b[:-3] = a[3:] > > In [4]: b > Out[4]: array([3, 4, 5, 6, 7, 8, 9, 0, 0, 0]) > > Chuck > > > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion > > Thanks, Your ways are more obvious than my first approach. With a bit more playing I get a one-liner: c=np.append(a[3:], [0]*3) -- Gökhan
_______________________________________________ NumPy-Discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
