Hi All, Below is some array behaviour which i think is odd >>> a=arange(10) >>> a array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> b=nonzero(a<0) >>> b (array([], dtype=int32),) >>> if not b[0]: ... print 'b[0] is false' ... b[0] is false
Above case the b[0] is empty so it is fine it is considered false >>> b=nonzero(a<1) >>> b (array([0]),) >>> if not b[0]: ... print 'b[0] is false' ... b[0] is false Above case b[0] is a non-empty array. Why should this be consider false. >>> b=nonzero(a>8) >>> b (array([9]),) >>> if not b[0]: ... print 'b[0] is false' ... >>> Above case b[0] is non-empty and should be consider true.Which it does. I don't understand why non-empty array should not be considered true irrespective to what value they have. Also, please suggest the best way to differentiate between an empty array and non-empty array( irrespective to what is inside array). Thanks, Shailendra _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
