El dc 20 de 06 del 2007 a les 12:43 -0700, en/na Michael McNeil Forbes va escriure: > Hi, > > That is a little more complicated than I want, but it shows me the > solution: Construct the array of the desired shape first, then fill it. > > data = [1.0, 3,0] > keys = [('a',1),('b',2)] > > # Convert to arrays for indexing > data_array = array(data1) > key_array = empty(len(keys),dtype=tuple) > key_array[:] = keys[:]
the later two statements can also be written as: key_array = array(keys, dtype=tuple) > inds = argsort(data) > data_array[:] = data[inds] > key_array[:] = keys[inds] Yeah, much simpler than my first approach. Cheers, -- Francesc Altet | Be careful about using the following code -- Carabos Coop. V. | I've only proven that it works, www.carabos.com | I haven't tested it. -- Donald Knuth _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion