Alexander Michael kirjoitti:
> On 3/23/07, Nadav Horesh <[EMAIL PROTECTED]> wrote:
>
>> How about
>>
>> a = empty((5,7,4))
>> c = a[...,-1]
>>
>
> Solely because I want to use the array with code that assumes it is
> working with two-dimensional arrays but yet only performs operations
> on the "outer" two-dimensional array that would be consistent with an
> "inner" array type (i.e. scalar assignment, element-wise
> multiplication, etc.). I own all the code, so perhaps I can replace
> a[mask,-1] with a[mask,-1,...] and such. Hmm. Not bad reminder,
> thanks.
>
In some cases the 2d code works without modifications also for
3d-arrays, because in numpy
a[1,2]
is the same as
a[1,2,...]
for a 3d-array.
For example, the examples in your first post run as intended:
>>> from numpy import *
>>> a = empty((5,7,4), dtype=float64)
>>> c = a[:,-1] # shape (5,4) array, i.e. last column of 4 element arrays
>>> a[0,0] = 2.0
>>> print a[0,0]
[ 2. 2. 2. 2.]
>>> a[1,0] = 3.0
>>> a[0,1] = a[0,0] * a[1,0]
>>> print a[0,1]
[ 6. 6. 6. 6.]
--
Pauli Virtanen
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